Mr. Durani bought a gold chain for ₹1,80,000 and a car for ₹3,20,000. The value of the gold chain grows at 30% p.a., while the car depreciates by 20% in the first year and 15% p.a. thereafter. If both are sold after 3 years, find the profit or loss.

Mr. Durani – Gold Chain & Car Profit/Loss

Question

Mr. Durani bought a gold chain for ₹1,80,000 and a car for ₹3,20,000. The value of the gold chain grows at 30% p.a., while the car depreciates by 20% in the first year and 15% p.a. thereafter. If both are sold after 3 years, find the profit or loss.

⚡ Short Trick

Gold:
₹1,80,000 × 130/100 × 130/100 × 130/100 = ₹3,95,460

Car:
₹3,20,000 × 80/100 × 85/100 × 85/100 = ₹1,84,960

Total Selling Value:
₹3,95,460 + ₹1,84,960 = ₹5,80,420

Total Cost Price:
₹1,80,000 + ₹3,20,000 = ₹5,00,000

Profit = ₹5,80,420 − ₹5,00,000 = ₹80,420

📌 Formula

Appreciation:

A = P × (1 + R/100)n

Depreciation:

A = P × (1 − R/100)n

Profit/Loss:

Profit/Loss = Total SP − Total CP

📝 Long Form Solution

Gold Chain after 3 years:

₹1,80,000 × (1.30)3
= ₹1,80,000 × 2.197
= ₹3,95,460

Car after 3 years:

First year = ₹3,20,000 × 80/100 = ₹2,56,000
Second year = ₹2,56,000 × 85/100 = ₹2,17,600
Third year = ₹2,17,600 × 85/100 = ₹1,84,960

Total Selling Price:

₹3,95,460 + ₹1,84,960 = ₹5,80,420

Total Cost Price:

₹1,80,000 + ₹3,20,000 = ₹5,00,000

✅ Final Answer

₹80,420 Profit

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